50=-16x^2+63x-4

Solution for 50=-16x^2+63x-4 equation:

50=-16x^2+63x-4

We move all terms to the left:

50-(-16x^2+63x-4)=0

We get rid of parentheses

16x^2-63x+4+50=0

We add all the numbers together, and all the variables

16x^2-63x+54=0

a = 16; b = -63; c = +54;
Δ = b2-4ac
Δ = -632-4·16·54
Δ = 513
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{513}=\sqrt{9*57}=\sqrt{9}*\sqrt{57}=3\sqrt{57}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-63)-3\sqrt{57}}{2*16}=\frac{63-3\sqrt{57}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-63)+3\sqrt{57}}{2*16}=\frac{63+3\sqrt{57}}{32}
$